Question

A thin wire of length 40 cm is folded into a rectangle. If the length of the rectangle is 12cm, find its breadth? one more time plz

Answer 1

Solution

Given :-

• Length of wire = 40 cm
• Wire fold into in a rectangle .
• Length of rectangle = 12 cm

Find :-

• Breadth of rectangle

Explanation

Formula

$\dag\boxed{\underline{\tt{\orange{\: Perimeter_{rectangle}\:=\:2\times(Length+Breadth)}}}}$

According to question ,

When, wire fold into a rectangle

then, total length of wire will be same perimeter of rectangle .

That's mean,

• Length of wire = Perimeter of rectangle

Now, Calculate

==> Perimeter of rectangle = 2 × (Length + Breadth)

Keep above Value,

==> 40 = 2 × (12 + Breadth)

==> Breadth + 12 = 40/2

==> Breadth = 20 - 12

==> Breadth = 8

Hence

• Breadth of Rectangle will be = 8 cm

___________________

Answer 2

Answer:

40 सेमी लम्बाई के एक पतले तार को एक आयत में मोड़ा गया है। यदि आयत की लंबाई 12 सेमी है, तो इसकी चौड़ाई ज्ञात कीजिए?

Step-by-step explanation:

Have Given :-

• length of the wire = 40 cm

• length of the of the rectangle = 12cm

$\huge {\colorbox{cyan}{ \color{yellow}{Formula :- }}}$

$\scriptsize\bold{Parameter \: of \: rectangle = 2(l + b)}$

$\scriptsize\bold{ \because{The \: wire \: is \: bent \: over \: the \: rectangle.}}$

$\therefore \: 40 = 2(12 + b)$

$\frac{ \cancel{40}}{ \cancel2} = 12 + b$

$20 = 12 + b$

$20 - 12 = b$

$8 = b$

$breathe = 8 \: cm$