A thin wire of length L and uniform linear mass density p is bent into a circular coil Moment of inertia of the coil about tangential axis in its plane is_______
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Explanation:
Given: A thin wire of length L and uniform linear mass density ρ is bent into a circular coil.
To find the moment of inertia of the coil about the tangential axis in its plane
Solution:
The moment of inertia of the thin wire coil about its diameter
I=
2
1
MR
2
Here M=V×ρ (mass=volume × density)
and we know L=2πR⟹R=
2π
L
(as thin wire of length L is bent into a circular coil)
I=
2
1
MR
2
⟹I=
2
1
Lρ×(
2π
L
)
2
⟹I=
8π
2
L
3
ρ
Now using parallel axis theorem, we get
I
xx
′
=I+MR
2
⟹I
xx
′
=
8π
2
L
3
ρ
+Lρ(
2π
L
)
2
⟹I
xx
′
=
8π
2
L
3
ρ+2L
3
ρ
⟹I
xx
′
=
8π
2
3L
3
ρ
is the moment of inertia of the coil about the tangential axis in its plane8π
2
3L
3
ρ
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