Question

A thin wire of length l having linear densityp is bent into circular loop with C as its centre as shown in fig the moment of inertia of the loop about the line AB is
​

Answer 1

Explanation:

The moment of inertia of a thin hoop about its diameter is

2

1

MR

2

here, M=LP also, we have

2πR=L

⇒R=

2π

L

So, we have

I=

2

1

MR

2

=

2

1

LP(

2π

L

)

2

=

8π

2

L

3

P

Now using parallel axis theorem we have

L

xx

1

=I

cm

+MR

2

=

8π

2

L

3

P

+LP(

2π

L

)

2

=

8π

2

L

3

P

+

4π

2

L

3

P

=

8π

2

3L

3

P

Please mark me as Brainalist if it helps and follow me