A third of Arun's marks in mathematics exeeds a half of his marks in english by 80.if he got 240 marks In two subjects together how many marks did he got in english?
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Let the the marks obtained in maths = x,
And let the marks obtained in English = y,
Now form the equation for the first sentence,
x ÷ 3 = y ÷ 2 + 80
Now the equation for the second sentence is
x + y = 240
We can rewrite the first equation as
(2x - 3 y )÷ 6 = 80, i.e..
2x -3y= 480
And the second equation as ,
3x + 3y = 720
Now we can add the two equations, that results in
2x - 3 y + 3x + 3y = 480 + 720
i.e.. 5x = 1200
Thus x = 1200 ÷ 5
x = 240
Marks in mathematics = 240
Now , substituting in x + y = 240
240 + y = 240
y = 0
So marks obtained in English = 0
(PS- He failed in English )
And let the marks obtained in English = y,
Now form the equation for the first sentence,
x ÷ 3 = y ÷ 2 + 80
Now the equation for the second sentence is
x + y = 240
We can rewrite the first equation as
(2x - 3 y )÷ 6 = 80, i.e..
2x -3y= 480
And the second equation as ,
3x + 3y = 720
Now we can add the two equations, that results in
2x - 3 y + 3x + 3y = 480 + 720
i.e.. 5x = 1200
Thus x = 1200 ÷ 5
x = 240
Marks in mathematics = 240
Now , substituting in x + y = 240
240 + y = 240
y = 0
So marks obtained in English = 0
(PS- He failed in English )
anup103:
Hope it helps
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