Question

a thombus is 96 sq m. If its perimeter is 32 m, find its altitude,
ABCD is a square of side 14 cm and AED and BEC are semi-circles as shown in the figure. Find the area
of the shaded region
D
А
B
titude corresponding​

Answer 1

: The sides AB and CD of a quadrilateral ABCD

are extended to points P and Q respectively. Is

∠ADQ + ∠CBP = ∠A + ∠C? Give reason.

Solution : Join AC, then

∠CBP = ∠BCA + ∠BAC and

∠ADQ = ∠ACD + ∠DAC

(Exterior angles of triangles)

Therefore, ∠CBP + ∠ADQ = ∠BCA + ∠BAC + ∠ACD + ∠DAC

= (∠BCA + ∠ACD) + (∠BAC + ∠DAC)

= ∠C + ∠A

Answer 2

$altitude =12cm$

$area$ $of$ $shaded$ $region$ =$42 cm^{2}$

see the pic that i have attached

hope this helps...