A Thousand kilogram vehicle moving with a speed of 20 metre per second is brought to rest in a distance of 50 M find the acceleration and calculate the unbalanced force acting on the vehicle and the actual force applied by the applied by the break maybe slightly less than the calculated and give reason
Answers
Answered by
2
Data: mass of the body = 1,000 kg
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 m/s
Displacement (S) = 50 m
Force acting (F) =?
Solution:
We know that F = ma and 2as= v2 - u2 ⇒ 2 × a × 50 m = 02 - 202
a= -4 m/s2 now F = ma ⇒F = 1,000 × -4 = -4,0000N
Note: Negative symbol represents The opposit direction to the displacement.
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 m/s
Displacement (S) = 50 m
Force acting (F) =?
Solution:
We know that F = ma and 2as= v2 - u2 ⇒ 2 × a × 50 m = 02 - 202
a= -4 m/s2 now F = ma ⇒F = 1,000 × -4 = -4,0000N
Note: Negative symbol represents The opposit direction to the displacement.
Similar questions
Hindi,
7 months ago
Environmental Sciences,
1 year ago
Social Sciences,
1 year ago
Chemistry,
1 year ago
Math,
1 year ago
Chemistry,
1 year ago