Question

a three digit number 100 digits twice the tens digit while the unit digit is thrice the 10 digit also the sum of its digit is 18 find the number

Answer 1

let a be the tens place digit
then by given conditions
hundred place digit = 2a and
unit place digit = 3a
then sum of all is,
a + 2a + 3a = 18
i.e 6a = 18
hence a = 3
then the number will be
2a a 3a = 6 3 9
i.e the given number is 639.

Hope it will help you.....