. A three digit number 3a5 is added to anoth
number 12b8, which is divisible by 11. Then
a is added to another 3 digit number 933 to give a 4 digit
ible by 11. Then find the value fo a+b?
The product of the first 3 please answer it quickly its important please friends
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Answer:
3a5+12b8=15(a+b+1)3+933=24(a+b+4)6/11=0
a+b=(2+a+b+4)-(4+6)
=6+a+b-10=0
=-4+a+b=0
=a+b=4
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