a three digit number 4A3 is added to another three digit number 984 to give four digit number 13B7 which is divisible by 11 find a + b
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Solution:
given
. 4a3
+984
-------
13b7
The first thing is to figure out the possible values of the sum. The missing digit can be 0 to 9:
1307, 1317, 1327, 1337, 1347, 1357, 1367, 1377, 1387, 1397
Only one of these is evenly divisible by 11, namely 1397, so b = 9.
Filling that in, we have:
. 4a3
+984
-------
1397
From that it is easy to figure the top number is 413 and thus a = 1.
a=1
b=9
a+b = 10
Answer:
10
Solution:
given
. 4a3
+984
-------
13b7
The first thing is to figure out the possible values of the sum. The missing digit can be 0 to 9:
1307, 1317, 1327, 1337, 1347, 1357, 1367, 1377, 1387, 1397
Only one of these is evenly divisible by 11, namely 1397, so b = 9.
Filling that in, we have:
. 4a3
+984
-------
1397
From that it is easy to figure the top number is 413 and thus a = 1.
a=1
b=9
a+b = 10
Answer:
10
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