Question

a three digit number 4BC is divisible by 15 what are the values of Band C for the smallest such number​

Answer 1

Answer:

Here we go...

Prime factorisation of 22=2x11

Prime factorisation of 33=3x11

Prime factorisation of 55=5x11

So, LCM 22,33,55=2x3x5x11=330

As 330 is the smallest 3-digit number divisible by 22,33,55, the number 330+5=335 will give a

remainder 5 when divided by these numbers.

The highest 3- digit number is 999.

999 when divided by 330 gives a remainder 9, so 999-9=990 is the largest 3-digit number

divisible by 22,33,55, the number 990+5=995 will give a remainder 5 when divided by these

numbers.

I hope that helps