Question

A three digit number abc is 459 more than the sum of its digit what is the sum of the two digit number abn one digit number

Answer 1

Answer:

The sum is 51

Step-by-step explanation:

The three digit number abc can be written as 100a + 10b + c

Sum of digits = a + b + c

As per the question three digit number is 459 more than sum of its digits

That is,

100a + 10b + c = 459 + a + b + c

100a - a + 10b - b + c - c = 459

99a + 9b = 459

Dividing the equation by 9,

11a + b = 51       (Let this be eqn 1)

We have to find,

Sum of two digit number ab and one digit number a

= 10 a + b + a

= 11 a + b

Putting the value of 11 a + b from eqn 1

= 51

Hence sum = 51

Answer 2

Answer:

51 is the answer mark as brainlist