Question

A three-digit number is chosen at random. Find the probability that it is a multiple of 7.

Answer 1

Answer:

Total three digit numbers =(999–100)+1=900

Total even numbers between them =450

(Working for above:

If the largest even number be the nth term for a arithmetic progression wherein the difference is 2 (even numbers) then there are a total of n terms.

The largest even number among the numbers is 998.

Since tn=a+(n-1)*d

998=100+(n-1)*2

898=(2n-1)*2

449=n-1

450=n

Hence therr are 450 even mumbers in total between 100 and 999.)

Now,

Probability =450/900

=1/2

Step-by-step explanation:

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Answer 2

Answer:

P(E)=7÷900 = 0.0077

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