Question

A three digit number is chosen find the probability at all three digits are not same

Answer 1

Answer:

the probablity will be as shown

Step-by-step explanation:

you have to find the square by the least then the answer will be divided by the half of number as shown in ur answer

Answer 2

The probability would be 0.72

Step-by-step explanation:

Since, In a number,

Digits are 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9,

So, the total possible numbers of 3 digits = 9 × 10 × 10 = 900,

Note : first digit can not be zero in the three digit number.

If the digits are different,

Total ways of selecting first digit = 9, ( excluded 0)

Ways of selecting second digit = 9, ( included 0 and excluded first digit ),

Ways of selecting third digit = 8, ( included 0 and excluded first and second digit ),

Thus, total ways of selecting a three digit number having different digits = 9 × 9 × 8

= 648,

$\because \text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Thus, the probability of selecting a three digit number having different digits

$=\frac{648}{900}$

= 0.72

#Learn more:

Find probability:

https://brainly.in/question/7971174