Question

A three digit number is to be formed using digits 3,4,7,8 without repetition. The probability that it is an odd number is?

Answer 1

Step-by-step explanation:

1st

437 it is odd

2nd

843 it is odd

3rd

873 it is odd

and many so

Answer 2

$\fontsize{18}{10}{\textup{\textbf{The required probability is 50 percent.}}}$

Step-by-step explanation:

Since we have four digits to use (3, 4, 7 and 8), out of which two are odd and two are even.

So, for the unit digit of the three digit number, we have 2 options, since the number should be odd.

For ten's digit, we have 3 options since repetition is not allowed.

For hundred's digit, we have 2 options left.

That is, the number of three digit odd numbers that can be formed with 3, 4, 7 and 8 is

$m=2\times3\times2=12.$

And, the total number of 3 digit numbers that can be formed without repetition is

$n=2\times3\times4=24.$

Therefore, the probability is given by

$p=\dfrac{m}{n}=\dfrac{12}{24}=0.5=50%.$

Thus, the required probability is 50%.

#Learn more

Question : A die is rolled, find the probability that an odd number is obtained.

Link : https://brainly.in/question/9657438.