Question

a three gallon contains one part S and 2parts R inorder to change it to mixture containing 25%S how much R should be added​

Answer 1

Answer:

1 Gallon R should be added

Step-by-step explanation:

A three gallon contains one part S and 2parts R inorder to change it to mixture containing 25%S how much R should be added​

One Part S

2 Part R

S = (1/(1 + 2)) * 3 = 1 gallon

R = (2/(1 + 2)) * 3 = 2 gallon

Let say X  gallon R is added

Then Mixture = 3 + X  Gallon

S to be 25 %

=> (1/(3 + X)  * 100 = 25

=> 3 + X = 4

=> X = 1

1 Gallon R should be added