Question

A three hinged arch is loaded with an isolated load 1000 kg at a horizontal distance of 2.5 m from the crown, 1 m above the level of hinges at the supports 10 metres apart. The horizontal thrust is (a) 1250 kg (b) 125 kg (c) 750 kg (d) 2500 kg answer: option a

Answer 1

H = wl2/8h this formula is not apply when apply H = 781kg why answer is 1250kg.

Answer 2

Given,

Weight of the isolated load=100kg,

Distance from the crown=2.5m,

To find,

Value of the horizontal thrust.

Solution,

We know the horizontal thrust is applied to both bolt action rifles.

So, the formula of horizontal thrust is,

Horizontal thrust=load× horizontal distance/2×distance above the hinges

H=px/2h

  =1000×2.5/2×1

  =2500/2

  =1250kg

Hence, the horizontal thrust is 1250kg.