(a) three resistor 2 ohm,4ohm,5ohm are combined in paralle. what is the total resistance of the combination? (b) if the combination is connected to a battery of emf 20v and negligible internal resistance, determine the current through each resistor,and the total current drawn from the battery.
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total resistance will be 1/2+1/4+1/5=10+5+4/20=19/20 ohm
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(a). Three resistance in parallel of values 2, 4, & 5 ohms. Therefore, resultant resistance R is
1 / R = 1/ 2 + 1/4 + 1/5
1/R = (10 + 5 + 4) / 20
R = 20 / 19 ohms
(b). Emf (V) = 20 v
R = 20 / 19 ohms
Therefore, total current I = V / R
= 20 / (20/19)
= 19 amps
Current through 2 ohms is
= 20 / 2 = 10 amps
Current through 4 ohms
= 20 / 4 = 5 amps
Current through 5 ohms
= 20 / 5 = 4 amps
Therefore, the total current through circuit is 19 Amps and the current through resistance 2, 4 & 5 ohms are 10, 5 & 4amps respectively.
1 / R = 1/ 2 + 1/4 + 1/5
1/R = (10 + 5 + 4) / 20
R = 20 / 19 ohms
(b). Emf (V) = 20 v
R = 20 / 19 ohms
Therefore, total current I = V / R
= 20 / (20/19)
= 19 amps
Current through 2 ohms is
= 20 / 2 = 10 amps
Current through 4 ohms
= 20 / 4 = 5 amps
Current through 5 ohms
= 20 / 5 = 4 amps
Therefore, the total current through circuit is 19 Amps and the current through resistance 2, 4 & 5 ohms are 10, 5 & 4amps respectively.
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