A three unbiased coins are tossed together find the probability of getting aleast two heads n atmost two heads
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Total outcomes
HHH
HHT
HTH
THH
TTH
HTT
THT
TTT
These are the total possibliltes and there are total 8 outcomes.
Probability of getting aleast two heads n atmost two heads = No of favourable outcomes / total number of outcomes
Favourable outcomes are
HTH
HHT
THH
HTT
THT
TTH
Thus,
Probability = 6 / 8 = 3/4 = 0.75.
HHH
HHT
HTH
THH
TTH
HTT
THT
TTT
These are the total possibliltes and there are total 8 outcomes.
Probability of getting aleast two heads n atmost two heads = No of favourable outcomes / total number of outcomes
Favourable outcomes are
HTH
HHT
THH
HTT
THT
TTH
Thus,
Probability = 6 / 8 = 3/4 = 0.75.
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