Question

A THREE-WHEELER SCOOTER CHARGES Rs 10 FOR THE FIRST KILOMETER AND Rs4.50 EACH FOR EVERY SUBSEQUEMET KILOMETER. FOR A DIRTANCA OF X KM,AN AMOUNT OF RS.Y IS PAID.WRITE THE LINEAR EQUATION REPRESENTING THE ABOVE INFORMATION.

Answer 1

Let the distance travelled be - X
Let the total Fare be - Y
Therefore.. According to the question,
For the first km it is rs 10 and for the subsequent kms it is rs 4.50 per km
Therefore the linear equation is
10+4.50X=Y
Or
4.50X-Y=10

Answer 2

Answer:

$\text{The linear equation is }4.5X-Y=-5.5$

Step-by-step explanation:

Given that a three-wheeler scooter charges Rs 10 for the first kilometer and Rs 4.50 each for every subsequent kilometer. For a distance of X km an amount of Rs Y is paid.

we have to write the linear equation representing the above.

Let the distance travelled be - X

Let the total Fare be - Y

∴ According to the question,

For the first km the fare is Rs 10 and for the subsequent kms it is Rs 4.50 per km.

Therefore the linear equation is

$10+4.50(X-1)=Y$

⇒ $10+4.5X-4.5=Y$

⇒ $4.5X+5.5=Y$

⇒ $4.5X-Y=-5.5$