A three wheeler taxi charges 15rupees for first kilometre and 8rupees each for every subsequent kilometre . For a distance of Xkm and amount of Yrupees is paid . Form a linear equation to represent the above equation.
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Total distance covered = x km
Fare for 1st kilometre = Rs 8
Fare for the rest of the distance = Rs (x − 1) 5
Total fare = Rs [8 + (x − 1) 5]
y = 8 + 5x − 5
y = 5x + 3
5x − y + 3 = 0
Here is the complete explanation to the mentioned question.
Fare for the first km = Rs 8
Total distance covered = x km
After travelling first km, remaining distance = (x – 1) km
Rate of fare = Rs 5 per km
Fare for (x – 1) km = 5 × (x –1)
Total fare = Rs y
Fare for the first km + fare for the remaining distance = y
8 + (x – 1) 5 = y
8 + 5x – 5 = y
5x – y + 3 = 0
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