Question

A thrust of 20N is acting on an area of 2m2. How much pressure is
acting on the surface?
a. 5 Nm-2
b. 10 Nm-2
c. 20 Nm-2
d. 40 Nm-2​

Answer 1

Answer:

10Nm-2

P=F/A

=20/2=10

PLEASE mark it as BRAINLIEST ANSWER

Answer 2

Gɪᴠᴇɴ :-

• Thrust (F) = 20N
• Area = 2m²

ᴛᴏ ғɪɴᴅ :-

• Pressure(P)

sᴏʟᴜᴛɪᴏɴ :-

We know that,

$\implies \sf \: Pressure(P) = \frac{Force(F)}{Area(A)} \\ \\ \implies \sf \: P = \frac{F}{A}$

On putting above given values in it, we get,

$\implies \sf \: P = \frac{20}{2} \\ \\ \implies \sf \: P = 10N {m}^{ - 2}$

Hence,

• Pressure(P) = 10 N/m²

Therefore,

➦ Option (b) 10Nm-2 is correct.