A ticket is randomly selected from abasket containing 3 green ,4 yellow ,5 blue ticket determine the probabilty of getting a green ticket
ranaisha123451:
1/4 or 3/12
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Total no. Of balls _12
Probability of getting green ball is 3/12
The answer is _ 4.
Hope it helps you.
Probability of getting green ball is 3/12
The answer is _ 4.
Hope it helps you.
Answered by
0
Answer:
sample space = { g1 ,g2, g3, y1, y2, y3, y4, b1, b2, b3,b4, b5}
n(S) = 12
event A getting green ticket.
A= { g1 ,g2, g3}
n(A)= 3
P(A)=n(A)/ n(S)
= 3/12
= 1/4
Step-by-step explanation:
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