Question

A ticket raffle consists of 20 prizes. The first prize is P25,000, and each successive prize is P500 less than the preceding prize. What is the value of the 19th prize?

Answer 1

Answer:

P16000

Step-by-step explanation:

this is in the form of an AP(Arithmetic progression)

a = 25000

d = -500

n = 19

an = a + (n-1)d

a19

= a + 18d

= 25000 - 9000

= 16000

Answer 2

Answer:

P16,000

Step-by-step explanation:

Here the prizes decrease in the form of an AP.

With a = 25000 and d = -500

To find the value of the nineteenth prize, use the formula

$a_{n} = a + (n-1)d$

Plugging in the values (here n = 19)

$a_{19} = 25000 + (19-1)(-500)\\= 25000 + (18)(-500)\\= 25000 - 9000\\= 16000$

Hence the value of the nineteenth prize would be P16,000.