A ticket vending machine has created 20 tickets numbered from 1 to 20. if a ticket is chosen at random what is the probability that the ticket has a number which is either a multiple of 3 or multiple of 5?
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Here S = {3,5,6,9,10,12,15,18,20}
Let E = event of getting a multiple of 3 or 5 = {3,5,6,9,10,12,15,18,20}
P(E) =n(E)/n(S) = 9/20
Hope this helps you out.
Let E = event of getting a multiple of 3 or 5 = {3,5,6,9,10,12,15,18,20}
P(E) =n(E)/n(S) = 9/20
Hope this helps you out.
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