Question

A tiger came accelerates from rest at the rate of 4 metre per second square
A) what will be the velocity of tiger after 10 seconds
B) how far will it go? (find distance) ​

Answer 1

Given that acceleration, a = 4 m/s² ;  Time(t) = 10 s
a) Initial velocity= 0 ; Final velocity= v
       v = u + at
   ⇒ v = 0 + 4×10 = 40 m/s
b) Displacement, S = ut + 1/2 at²
                             = 0×10 + (1/2) 4 × (10)²
                             = 200 m
So, the cheetah will travel 200m far with a velocity of 40m/s in 10s duration of time.

Or

Acceleration of cheetah (a) = 4m/s²
time = 10s
initial velocity(u) = 0
final velocity = v
distance travelled = s

v = u +at = 0 + 10×4 = 40m/s
s = (v²-u²)/2a = 40²/(2×4) = 1600/8 = 200m