Question

A tiger is at 40 of its own leaps behind a deer. The tiger takes 6 leaps per minute to the deer’s 5 leaps. If the tiger and the deer cover 5 m and 4 m per leap respectively, what distance will the tiger have to run before it catches the deer?​

Answer 1

Answer:

600m

Step-by-step explanation:

First let us convert all those leaps in distances (in m)

tiger is 40*5=200m behind deer

tiger can travel 6*5=30m per minute and deer 4*5=20m per minute

let the total time for which they would be running be X minutes

total distance travelled by deer =20x and tiger =200+20x

total distance travelled by tiger is also equal to 30x

30x = 200 +20x

10x= 200

X=20 minutes

total distance travelled by tiger =30x =30*20=600m

NOTE :- X and x are same variables so don't confuse