Question

a tiger starting from rest attains an acceleration of 4m/s² in 10 second find its final velocity and the distance travelled​

Answer 1

Answer:

V=40m/s

s=200m.

Explanation:

u=0

a=4m/s^2

t=10s

v=u+at

v=4×10+0

v=40m/s (final velocity)

2as=v^2-u^2

2×4×s=(40)^2-0^²

8s=1600

s=200m(distance travelled).

Answer 2

Answer:

V=40m/s

s=200m.

Explanation:

u=0

a=4m/s^2

t=10s

v=u+at

v=4×10+0

v=40m/s (final velocity)

2as=v^2-u^2

2×4×s=(40)^2-0^²

8s=1600

s=200m(distance travelled).

Explanation: