Question

A tile has the shape of a parallelogram whose base is 35 cm and the corresponding height is 10 cm.How many tiles are required to cover a floor of area 84000 cm².

Answer 1

$\large{\underline{\bf{\purple{Given:-}}}}$

• ✶ Base of Tile = 35cm
• ✶ Shape of Tile = parallelogram
• ✶ Height of tile = 10cm
• ✶ Area of floor = 84000cm²

$\large{\underline{\bf{\purple{To\:Find:-}}}}$

• ✶ Number of tiles required to cover a floor of area 84000cm².

$\huge{\underline{\bf{\red{Solution:-}}}}$

All tiles are in the shape of parallelogram.

$\boxed {\pink {\rm{Area \: of \: parallelogram = base \: \times height}}}$

➝ Area of 1 tile = base × height

➝ Area of 1 tile = 35 ×10

➝ Area of 1 tile = 350cm²

Now,

Area of floor = 84000cm²

Number of tiles required to cover floor

= Area of floor/Area of 1 tile

➝ 84000/350

➝ 8400/35

➝ 240

So,

240 tiles are required to cover a floor of area 84000cm²

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Answer 2

$\huge{\underline{\underline{\pink{Ans}\red{wer:-}}}}$

$\sf{240 \ tiles \ are \ required \ to \ cover}$

$\sf{the \ floor.}$

$\sf\orange{Given:}$

$\sf{For \ parallelogram \ shaped \ tile,}$

$\sf{\implies{Base(b)=35 \ cm}}$

$\sf{\implies{Height (h)=10 \ cm}}$

$\sf{\implies{Area \ of \ floor=84000 \ cm^{2}}}$

$\sf\pink{To \ find:}$

$\sf{Number \ of \ tiles \ required \ to \ cover}$

$\sf{the \ floor.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Area \ of \ parallelogram=base(b)\times \ height(h)}$

$\sf{…formula}$

$\sf{\therefore{Area \ of \ tile=35\times10}}$

$\sf{=350 \ cm^{2}}$

$\sf{Number \ of \ tiles \ required}$

$\sf{=\frac{Area \ of \ floor}{Area \ of \ tile}}$

$\sf{=\frac{84000}{350}}$

$\sf{=240}$

$\sf\purple{\tt{\therefore{240 \ tiles \ are \ required \ to \ cover}}}$

$\sf\purple{\tt{the \ floor.}}$