Question

A tile is a square of side 30 cm . How many such tiles would be required to cover the floor of a square room of side 600 cm

Answer 1

Answer:

Step-by-step explanation:

Side of the square room is 6m

then area of square room =side whole square

area =6×6

area=36m^2

side of square tile is 30cm

Then area of the square tile =side whole square

area=30×30

area =900cm^2

area=0.09m^2

no. of tiles required to cover the floor of a square room is 36/9×10^-2

=36×10^2/9

=4×10^2

=400m^2

Thank you

Answer 2

Answer:

400 Tiles required to cover the floor

Step-by-step explanation:

According to the information provide in the question it is given as

Size of tile = square = side =30 cm

Floor square type = side = 600 cm

We need to find the number of tiles required for floor

Here it is given that tile is of square shape so first we find the  area of tiles that is area of square

Area of 1 tiles = $side^{2}$

putting the values

$A = 30^{2}$

$A = 30\times 30\\A =900cm^{2}$

Now secondly we find the are of floor that is area of square

Area of floor = $side^{2}$

Putting the values

$A= 600^{2}$

$A = 600\times 600\\A =360000 cm^{2}$

Number of tiles required = Area of floor /area of 1 tiles

Substituting the values we get the answer

$T = \frac{360000}{900}$

(Reducing or cutting zeros on numerator and denominator )

Converting to the lowest term

$T=\frac{3600}{9} \\T= 400 tiles$

Hence  400 tiles required to cover the floor