a tile is a square of side 30 cm. how many such tiles would be required to cover the floor of a room of size 6 m by 3 m
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Answered by
7
Area of tile = 30× 30 cm²
Area of floor = 600×300 cm²
Therefore number of tiles required =
600×300/30×30
= 2 × 100
= 200 tiles
Area of floor = 600×300 cm²
Therefore number of tiles required =
600×300/30×30
= 2 × 100
= 200 tiles
Answered by
5
Area of floor = (6 × 3) m²
= 18 m²
= (18 × 10,000) cm²
= 180,000 cm²
Area of 1 tile = 30² cm²
=(30 × 30) cm²
= 900 cm²
∴ Required no. of tiles
= Area of floor / Area of 1 tile
= 180,000 cm² / 900 cm²
= 180,000 / 900
= 200
Hence, 200 tiles are required.
Explaination -
The floor is in the shape of a rectangle. Area of rectangle is Length times Breadth.
The tile is in the shape of square. Area of square is Side times Side.
Hope it helps ツ
= 18 m²
= (18 × 10,000) cm²
= 180,000 cm²
Area of 1 tile = 30² cm²
=(30 × 30) cm²
= 900 cm²
∴ Required no. of tiles
= Area of floor / Area of 1 tile
= 180,000 cm² / 900 cm²
= 180,000 / 900
= 200
Hence, 200 tiles are required.
Explaination -
The floor is in the shape of a rectangle. Area of rectangle is Length times Breadth.
The tile is in the shape of square. Area of square is Side times Side.
Hope it helps ツ
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