Math, asked by poojasingh7668, 1 year ago

a tile is a square of side 30 cm. how many such tiles would be required to cover the floor of a room of size 6 m by 3 m

Answers

Answered by AnanyaSrivastava999
7
Area of tile = 30× 30 cm²
Area of floor = 600×300 cm²

Therefore number of tiles required =
600×300/30×30
= 2 × 100
= 200 tiles
Answered by BlackVenom05
5
Area of floor = (6 × 3) m²

= 18 m²

= (18 × 10,000) cm²

= 180,000 cm²

Area of 1 tile = 30² cm²

=(30 × 30) cm²

= 900 cm²

∴ Required no. of tiles

= Area of floor / Area of 1 tile

= 180,000 cm² / 900 cm²

= 180,000 / 900

= 200

Hence, 200 tiles are required.

Explaination -

The floor is in the shape of a rectangle. Area of rectangle is Length times Breadth.

The tile is in the shape of square. Area of square is Side times Side.

Hope it helps ツ

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