Question

a tile measuring 50 cm × 50 cm has been designed to bear a pressure of 40N/m2. Find the force.​

Answer 1

Explanation:

${\huge{\rm{\underline{\underline{Given}}}}}$

Side of tile = 50cm

We know,

1m = 100cm

100 cm = 1 m

1 cm = $\displaystyle\frac{1}{100}$

50 cm = $\displaystyle\frac{50}{100}$

50 cm = $\displaystyle\frac{1}{2}$

50 cm = 0.5 m

Solution:

Area of tile = $(side)^2$

= 0.5 x 0.5

Area of tile = $0.25 m^2$

It is given that tile can carry a pressure of $200N/m^2$. If the force applied by this pressure is F,

F = Pressure x Area to tile

F = 200 x 0.25

F = 2 x 25

F = 50 N

Hence, It can withstand any force less than 50 N

Answer 2

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