Question

A time dependent force f=10t is applied on 10kg block.Find out the work done in 2 sec

Answer 1

Answer:

F= ma = 10 * dv/dt.....

.t= dv/dt ( mass is 10kg..both get cancelled)...

. Integration( t dt) = integration( dv)....... t^2/2 = v...... v= 4/2 ( t=2s).....v= 2m/s.....v= u + at..... a = 2/2....a= 1m/s^2...... S = ut + 1/2 at^2........ S= 1/2 * 1 * 4 ( u=0m/s)..... S = 2m.........WORK = F * S...... WORK = 10 * 2.....Therefore work = 20J.

HOPE IT HELPS AND PLZ MARK IT AS BRAINLIEST.......

Answer 2

Hope it helps.

Thank You