Question

A time period of 10^-8 s is called a shake. then, a lecture period of 50 min=……. shakes *
1 point
(A) 5 x 10^-7
(B) 8.3 x 10^-7
(C) 5 x 10^9
(D) 3 x 10^11​

Answer 1

Given :-

• 10⁻⁸ s is called a shake

We need to find :-

• 50min = _____ shakes

Solution :-

◍ As we know that :-

• 1 shake = 10⁻⁸ s → into minutes → 10⁻⁸/60 min

By simplifying

➜ 10⁻⁸/60 min = 1 shake

➜ 10⁻⁸ min = 60 shakes

➜ 1/10⁸ min = 60 shakes

➜ 1 min = 60 × 10⁸ shakes

Now finding for 50 minutes

☞ 50 min = 60 × 50 × 10⁸

☞ 50 min = 3000 × 10⁸

☞ 50 min = 3 × 10³ × 10⁸

☞ 50 min = 3 × 10¹¹

Conclusion :-

✤ 50 min = 3 × 10¹¹ shakes

Answer 2

Explanation:

A time period to 8 is call s