Question

A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?
A) 58 l
B) 65 l
C) 50 l
D) 62 l

Answer 1

A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

A) 58 l
B) 65 l
C) 50 l✔
D) 62 l

ĀNSWĒR ⏬⏬
  C) 50 l 

Explanation:

Let the tin contain 5x litres of liquids

(5x - 45) x 4/5/(5x - 45) x 1/5 + 45 = 2/5

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B


THANKS ✌✌


# NAVI ❤ HARYANVI ♠

= (70 - 45) x 15 + 45 

= 50 litres.

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer...

Let the tin contain 5x litres of liquids

=> [(5x - 45)x 4/5] / (5x - 45)x 1/5 + 45 =2/5

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B

=> 70 - 45)x 1/5 + 45

=> 50 litres.
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