Question

A tin box of length 9 metres, breadth 2 metres and height 50 cm is made
without a lid. Find the total area of its faces. Please tell with method plz
​

Answer 1

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$\underline{\bf \blue {Given}}\begin{cases} & \sf{\bullet\:Length\:of\;tin\;box = \bf{9\;m}} \\ & \sf{\bullet\:Breadth\;of\;tin\;box = \bf{2\;m}} \\& \sf{\bullet\:Height\:of\:tin\:box = \bf{50\:cm}} \end{cases}$

$\underline{\bf \blue {To\:find\::}}$

• $\sf Total \:surface\: area\: of\: tin \:box\:?$

$\underline{\bf \blue {Solution\::}}$

◍ Changing height from cm to m :-

$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{50}{100}\:$

$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{\cancel{50}}{\cancel{100}}\:$

$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\underline{\bf{0.5\:m}}\:$

◍ Formula that we will use :-

$\red\bigstar\:\boxed{\boxed{\sf \green{Total\:surface\:area_{(Cuboid)}\:=\:\bf{2(lb\:+\:bh\:+\:hl)}}}}$

◍ Putting all values in the formula :-

$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(9\:\times\:2\:+\:2\:\times\:0.5\:+\:0.5\:\times\:9)$

$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(18\:+\:1\:+\:4.5)$

$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2\:\times\:23.5$

$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:47$

$\underline {\boxed {\frak {\therefore \pink {Total\:surface\:area_{(Tin\:box)}\:\leadsto\:47\:m^2}}}}\:\purple\bigstar$

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Answer 2

Answer:

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$\begin{gathered}\underline{\bf \blue {Given}}\begin{cases} & \sf{\bullet\:Length\:of\;tin\;box = \bf{9\;m}} \\ & \sf{\bullet\:Breadth\;of\;tin\;box = \bf{2\;m}} \\& \sf{\bullet\:Height\:of\:tin\:box = \bf{50\:cm}} \end{cases}\\ \end{gathered}$

$\underline{\bf \blue {To\:find\::}}$

$\sf Total \:surface\: area\: of\: tin \:box\:?$

$\underline{\bf \blue {Solution\::}}$

◍ Changing height from cm to m :-

$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{50}{100}$

$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{\cancel{50}}{\cancel{100}}\::$

$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\underline{\bf{0.5\:m}}$

◍ Formula that we will use :-

$]\red\bigstar\:\boxed{\boxed{\sf \green{Total\:surface\:area_{(Cuboid)}\:=\:\bf{2(lb\:+\:bh\:+\:hl)}}}}$

◍ Putting all values in the formula :-

$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(9\:\times\:2\:+\:2\:\times\:0.5\:+\:0.5\:\times\:9):$

$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(18\:+\:1\:+\:4.5):$

$\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2\:\times\:23.5$

$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:47$

$\underline {\boxed {\frak {\therefore \pink {Total\:surface\:area_{(Tin\:box)}\:\leadsto\:47\:m^2}}}}$

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