A tin hold 16 1/6 liter of oil how many such tin will required to hold 313 1/2 litre of oil
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Answer:
Step-by-step explanation:
16 1/6 = 97/6
313 1/2 = 617/2
Tin needed = 617/2 / 97/6
= 617/2 x 6/97
20
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