Question

A tin of refined oil is 8 cm high and can contain 488 mL of oil. The manufacturer increases the height of the tin to 15 cm. How many mL can the new tin hold?​

Answer 1

Answer:

New tin can hold 919.3 ml

Step-by-step explanation:

Volume of oil = 488ml

Height = 8cm

Radius = ?

Volume =

$- > \pi {r}^{2} h$

$- > 488 = \frac{22}{7} \times {r}^{2} \times 8$

$- > 488 \times 7 = 22 \times {r}^{2} \times 8$

$- > 3416 = 22 \times {r}^{2} \times 8$

$- > \frac{3416}{22 \times 8} = {r}^{2}$

$- > {r}^{2} = 19.5$

$- > r = \sqrt{19.5}$

New height = 15cm

Volume =

$- > \pi {r}^{2} h$

$- > \frac{22}{7} \times ({ \sqrt{19.5} )}^{2} \times 15$

$- > \frac{22}{7} \times 19.5 \times 15$

$- > 919.3 \: ml \: (approx)$

I hope it helps u dear friend ^_^♡♡