Question

A tin of refined oil is 8cm high and can contain 352g of oil The manufacturer increases the height of the tin to 12.5cm how much grams the new tin hold

Answer 1

The tin can hold 550 grams of oil.

Step-by-step explanation:

Given data:

• Volume of oil = 352 g
• Height = 8 cm
• Radius = ?

Solution:

Volume = πr^2 h

352 =  22/7 x r^2 x 8

r^2 = 352 x 7 / 22 x 8

r^2 = 14

r = √14 cm

New height = 12.5 cm

Volume = πr^2 h

V =  22/7 x √14 x √14 x 12.5

V = 22/7 x 14 x 12.5

V = 22 x 2 x 12.5

V = 550 g

Hence the tin can hold 550 grams of oil.

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The dimensions of an oil tin are 26 cm × 26 cm × 45 cm. find the area of the tin sheet required for making 20 such tins. if 1 sq m of the tin sheet costs rs 10, find the cost of tin used for these 20 tins. ?

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Answer 2

Answer:

★New tin can hold 550 gram of oil★

Step-by-step explanation:

Given:

• Height of tin 8 cm
• Tin can contain 352 g of oil ( Volume)
• Manufacturer increased the height of tin to 12.5

To Find: How much oil the new tin can hold?

Solution: Let Radius of tin be r cm

Therefore its volume will be πr²h

According to the question we have,

$\small\implies{\sf }$ πr²h = 352g³

$\small\implies{\sf }$ 22/7 x r² x 8 = 352g³

$\small\implies{\sf }$ r² = 352 x 7 / 22 x 8

$\small\implies{\sf }$ r² = 2464 / 176

$\small\implies{\sf }$ r² = 14 or r = √14

★ New Height = 12.5 cm and Radius= r (√14)

So,It's volume will be πr²h

$\small\implies{\sf }$ 22/7 x (√14)² x 12.5

$\small\implies{\sf }$ 22/7 x 14 x 12.5

$\small\implies{\sf }$ 22 x 2 x 12.5

$\small\implies{\sf }$ 550 g

Hence, The new tin can hold 550g