Question

a tin of sugar weighs 1200 g when it is 1/2 full and 1875 g when it is 7/8 full with the weight of the tin.how many grams of sugar can it hold when it is completely full?

Answer 1

Weight of the tin = $x$
Therefore,
[tex]x=2X1(200-x) \\ x=2400-2x \\ 3x=2400 \\ x=2400/3 \\ x=800[/tex]
Therefore, Amount of sugar when the tin is $\frac{1}{2}$ full = $1,200 - 800 grams = 400 grams$
Therefore, Amount of sugar the tin can can hold when it is full = $2 * 400 grams = 800 grams$