Question

A tinmaker converts a cubical metallic box into 10 cylinders tins. Side of a cube is 50cm and radius is 7cm. Find the height of each cylinder so made if the wastage of 12% is incurreal in the process

Answer 1

Step-by-step explanation:

volume of the cube= (50cm)^3= 125000cm^3

waste= 12% of cube= 12/100 *125000= 15000 cm³

10(volume of cylinder)= 15000cm^3

10(πr²h)= 15000cm³

22/7 *7cm*7cm*h= 15000cm³/10

154cm²h=1500cm³

h= 1500cm³/154cm²= 9.74 (approx)

hope this help

Answer 2

The height of cylinder=9.74 cm

Step-by-step explanation:

Side of cube=50 cm

Radius of cylinder=7 cm

Volume of cube=$(sid)^3=(50)^3=125000cm^3$

12% of 125000=$\frac{12}{100}\times 125000=15000cm^3$

Volume of cylinder=$\pi r^2h$

Where r= Radius of circle

$\pi=\frac{22}{7}$

h=Height of cylinder

Volume of cylinder=$\frac{22}{7}\times (7)^2h$

Volume of 10 cylinder=$10\times \frac{22}{7}\times 49h=1540h$

Volume of 10 cylinder=$15000cm^3$

$1540h=15000$

$h=\frac{15000}{1540}=9.74cm$

Hence, the height of cylinder=9.74 cm

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