A tiny air bubble inside a glass slab appears to be 6 cm deep when the viewed from one side and 4 cm deep when viewed from the other side. Assuming mu_("glass") = 3//2 . Find the thickness of slab.
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The thickness of slab is 15 cm.
Explanation:
The real depth and apparent depth relationship is given as:
ni/d = nr/d'
Where,
ni = Refractive index of incident medium
d = Distance of object
nr = Refractive index of refractive medium
d' = Apparent depth
The appearing depth from one side is:
∴ d' = 6 × 3//2 = 9 cm
The appearing depth from another side is:
∴ d'' = 4 × 3//2 = 6 cm
Now, the thickness of the slab is:
t = 9 cm + 6 cm
∴ t = 15 cm
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