Question

A tire is filled with air at 10°C to a gauge pressure of 2.5 atm. If the tire reaches a temperature of 35°C, what fraction of the original air must be removed if the original pressure of 2.5 atm is to be maintained

Answer 1

9% of original air should be removed.

Explanation:

We are given that:

10 + 273 = 283 °C

35 + 273 = 308 °C

PV = nRT

P1V1 = (n1)283 °C

P2V2 = (n2)308 °C

(n1)283 °C = (n2) 308 °C

283 / 308 = .91

Thus (n2) is 91 percent of (n1), and 9 percent should be removed.

9% of original air should be removed.