{a to the power -1/(a to the power -1 + b to the power -1)}+{a to the power -1/(a to the power -1 - b to the power -1)} = 2b to the power 2/(b to the power 2 - a to the power 2)
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(1/a÷1/a + 1/b)+ 1/a÷1/a -1/b =1/a÷b+a/ab+1/a÷b-a/ab =(1/a×ab÷b+a)+(1/a×ab÷b-a)=(b÷b+a)+(b÷b-a)= b (b-a)+b (b+a)÷(b+a)(b-a)=b^2-ba+b^2+ab÷b^2-a^2=2b^2÷b^2-a^2
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Answer:
a
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