Question

a
together and formed into a single
healuri
of which has an area of 81 m².​

Answer 1

What is the perimeter of a square whose area is 81m2 ?

The area of a square is A = s^2, where s is the length of one of the four congruent sides of the square.

The perimeter, i.e., the distance around a square is given by the formula P = 4s since a square has 4 congruent sides of length s.

To find the perimeter of a square whose area is equal to 81m^2, we need to first find the length of a side, s, of the square as follows:

A = s^2

81m^2 = s^2

s^2 = 81m^2 (Due to the symmetric property of equality, i.e., if a = b, then b = a)

Now, taking the positive square root since we can't have a negative length, we get:

(s^2)^(1/2) = (81m^2)^(1/2)

s = 9m

Therefore, the perimeter of the square is:

P = 4s

= 4(9m)

P = 36m