Math, asked by razlan5545, 1 year ago

A told b "i was five years older than you are now when you were born. I am one and a half times as old as i was then”. Find the present age of b?

Answers

Answered by shobharana009
0

Answer:


Step-by-step explanation:


Answered by AnkitaSahni
0

Given:

When B was born, A was five years older than B's present age

A's present age is one-and-a-half times as old as he was when B was born

To Find:

The present age of B

Let us assume:

Let the present age of B be x years

Let the present age of A be y years

Solution:

  • We will solve this question by making equations as per the conditions given.

Step 1: Write an equation for A's age when B was born.

  • When B was born, A was five more than B's present age.
  • So x years ago, A's age was equal to (y-x) years.

                                                 

                             ⇒  y-x = x +5                

                             ⇒ y = 2x + 5                                     (1)

Step 2: Find an expression for A's present age.

  • As compared to x years ago, A is now one and a half times older now.

                                ⇒ y = \frac{3}{2}(x + 5)

                                ⇒ 2y = 3x + 15

                                ⇒2 (2x + 5) = 3x + 15

                                ⇒ 4x + 10 = 3x + 15

                                ⇒ x = 5

Therefore, the present age of B is 5.

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