A told B ,“when i was as old as your now, then your age was four year less half of my present age". If the sum of present age of A and B is 61 years , what B's present age?(in year)
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Let their present ages be a and b respectively
Difference between A age and B age = a - b
So, when A was as old as B,the age of B then will be given by
b - (a - b) = a/2 - 4
2b - a = a/2 - 4
2b -3a/2 = -4
3a/2 - 2b = 4
3a - 4b = 8
Also, we have sum of their present ages
a + b = 61
Solving these 2 equations we get
a = 61 - b
3(61 - b) -4b = 8
183 - 3b -4b = 8
-7b = -175
b = 25
So, a = 36
Therefore, B's present age = 25 yrs
Difference between A age and B age = a - b
So, when A was as old as B,the age of B then will be given by
b - (a - b) = a/2 - 4
2b - a = a/2 - 4
2b -3a/2 = -4
3a/2 - 2b = 4
3a - 4b = 8
Also, we have sum of their present ages
a + b = 61
Solving these 2 equations we get
a = 61 - b
3(61 - b) -4b = 8
183 - 3b -4b = 8
-7b = -175
b = 25
So, a = 36
Therefore, B's present age = 25 yrs
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18
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hope this helps..u need to solve the whole question by substitution method
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