Question

A top of a ladder of length 15 cm reaches a window 9m above the ground. what is the distance between the base of the wall and that of the ladder?


Correct statements required
Explanation required ​

Answer 1

Answer:

Base = 12 m.

Step-by-step explanation:

By using pythagoras theorm.

H² = P² + B²

AB² = AC² + BC²

15² = 9² + x²

225 = 81 + x²

225 - 81 = x²

144 = x²

√144 = x

12 = x

BC = 12 m Answer.

Answer 2

Given :- Length of the ladder = 15m

height to the window = 9m

ATQ,

By Pythagoras Theorem

H^2=B^2+p^2

15^2=B^2+9^2

225=B^2+81

225-81=B^2

B^2=144

B=12m

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