Question

A torch bulb is 2.5v and 750mA. Calculate its resistance

Answer 1

Answer:

10 Joules

Explanation:

Given :

Given :V=2.5 V

Given :V=2.5 VI=750mA= 750x10⁻³A

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I           

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I             =2.5x750x10⁻³

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I             =2.5x750x10⁻³=1.875W

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I             =2.5x750x10⁻³=1.875Wreistance :

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I             =2.5x750x10⁻³=1.875Wreistance :V=IR

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I             =2.5x750x10⁻³=1.875Wreistance :V=IRR=V/I=2.5/750x10⁻³=3.3 ohms

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I             =2.5x750x10⁻³=1.875Wreistance :V=IRR=V/I=2.5/750x10⁻³=3.3 ohmsEnergy consumed if bulb is lighted for 4 hours :

Given :V=2.5 VI=750mA= 750x10⁻³Apower =p=?Power =V*I             =2.5x750x10⁻³=1.875Wreistance :V=IRR=V/I=2.5/750x10⁻³=3.3 ohmsEnergy consumed if bulb is lighted for 4 hours :E=p*t=1.875x4=7.500Wh=27x 10³ joules