A torch bulb is rated 2.5 V and 750 mA. Calculate (i) Its power (ii) its resistance and (iii) the energy consumed in 4 hours.
Answers
Answer:
PLEASE REFER TO THE ANSWER GIVEN BELOW
Explanation:
Given :
V=2.5 V
I=750mA= 750x10⁻³A
power =p=?
Power =V*I
=2.5x750x10⁻³
=1.875W
reistance :
V=IR
R=V/I=2.5/750x10⁻³=3.3 ohms
Energy consumed if bulb is lighted for 4 hours :
E=p*t=1.875x4=7.500Wh=27x 10³ joules
Answer:
Explanation:
- Potential difference (V)= 2.5 V
- Current = 750 mA = 0.75 A
- Time = 4 hr = 14400 s
- Power (P)
- Resistance (R)
- Energy (E)
Power:
→ Power is given by the formula
Power = Potential difference × Current
Power = 2.5 × 0.75
Power = 1.875 W
Resistance:
→ By Ohm's law resistance is given by
→ R = V/I
→ Substituting the datas we get,
R = 2.5 / 0.75
R = 3.33 Ω
Energy:
→ Energy is given by the formula,
Energy = Power × Time
Energy = 1.875 × 14400
Energy = 27000 J
→ Ohm's law state that the current flowing through a conductor is directly proportional to potential difference applied across its ends provided thatthe temperature and other physical conditions remain unchanged.
V = R I