A torch bulb is rated 2.5v and 750m calculate power resistance the energy consumed if the bulb is lighted for 4hrs
Answers
Answered by
4
v = 2.5 v
i = 750 mA = 0.75 A
t = 4hrs = 14400 sec
(A) P = VI
2.5 x 0.75 = 1.875 W
(B) R =V/I
2.5/0.75
3.33 Ω
(c) H = PT
= 1.875 X 14400
= 27000 J or 27 KJ
i = 750 mA = 0.75 A
t = 4hrs = 14400 sec
(A) P = VI
2.5 x 0.75 = 1.875 W
(B) R =V/I
2.5/0.75
3.33 Ω
(c) H = PT
= 1.875 X 14400
= 27000 J or 27 KJ
Similar questions